File:Grating Diffraction vs Period.webm
Summary
Description |
English: Diffraction from a sinusoidal grating as a function of its period. For long to intermediate periods, light is diffracted in 2 well-defined directions, but for very short periods light is not diffracted anymore. |
Date | |
Source | https://twitter.com/j_bertolotti/status/1484182956964864007 |
Author | Jacopo Bertolotti |
Permission (Reusing this file) |
https://twitter.com/j_bertolotti/status/1030470604418428929 |
Mathematica 12.0 code
\[Lambda]0 = 1.; k0 =
N[(2 \[Pi])/\[Lambda]0]; (*The wavelength in vacuum is set to 1, so \
all lengths are now in units of wavelengths*)
\[Delta] = \[Lambda]0/50; \[CapitalDelta] = 20*\[Lambda]0; (*Parameters for the grid*)
\[Sigma] = 20 \[Lambda]0; (*width of the gaussian beam*)
sourcef[x_, y_] := E^(-(x^2/(2 \[Sigma]^2))) E^(-((y + \[CapitalDelta]/ 2)^2/(2 (\[Lambda]0/2)^2))) E^(I k0 y);
\[Phi]in = Table[Chop[sourcef[x, y]], {x, -\[CapitalDelta]/2, \[CapitalDelta]/ 2, \[Delta]}, {y, -\[CapitalDelta]/2, \[CapitalDelta]/2, \[Delta]}]; (*Discretized source*)
d = \[Lambda]0/2; (*typical scale of the absorbing layer*)
imn = Table[ Chop[5 (E^-((x + \[CapitalDelta]/2)/d) + E^((x - \[CapitalDelta]/2)/d) + E^-((y + \[CapitalDelta]/2)/d) + E^((y - \[CapitalDelta]/2)/d))], {x, -\[CapitalDelta]/2, \[CapitalDelta]/2, \[Delta]}, {y, -\[CapitalDelta]/2, \[CapitalDelta]/2, \[Delta]}]; (*Imaginary part of the refractive index (used to emulate absorbing boundaries)*)
dim = Dimensions[\[Phi]in][[1]];
L = -1/\[Delta]^2*KirchhoffMatrix[GridGraph[{dim, dim}]]; (*Discretized Laplacian*)
stopstep[t_] := 10 (t - 1)^4 + 0.5;
frames = Table[
period = stopstep[t];
ren = Table[
If[-\[CapitalDelta]/2 < y < Cos[(2 \[Pi])/period x] - \[CapitalDelta]/2 + 3, 2, 1], {x, -\[CapitalDelta]/2, \[CapitalDelta]/2, \[Delta]}, {y, -\[CapitalDelta]/2, \[CapitalDelta]/2, \[Delta]}];
n = ren + I imn;
b = -(Flatten[n]^2 - 1) k0^2 Flatten[\[Phi]in]; (*Right-hand side of the equation we want to solve*)
M = L + DiagonalMatrix[SparseArray[Flatten[n]^2 k0^2]]; (*Operator on the left-hand side of the equation we want to solve*)
\[Phi]s = Partition[LinearSolve[M, b], dim]; (*Solve the linear system*)
ImageAdd[
ArrayPlot[Transpose[(Abs[(\[Phi]in + \[Phi]s)]^2/Max[(Abs[\[Phi]in + \[Phi]s]^2)[[(4 d)/\[Delta] ;; (-4 d)/\[Delta], (4 d)/\[Delta] ;; (-4 d)/\[Delta]]]])][[( 4 d)/\[Delta] ;; (-4 d)/\[Delta], (4 d)/\[Delta] ;; (-4 d)/\[Delta]]], ColorFunction -> "AvocadoColors", DataReversed -> True, Frame -> False, PlotRange -> {0, 1}]
,
ArrayPlot[ Transpose[Re[(n - 1)/5]] [[(4 d)/\[Delta] ;; (-4 d)/\[Delta], (4 d)/\[Delta] ;; (-4 d)/\[Delta]]], DataReversed -> True , ColorFunctionScaling -> False, ColorFunction -> GrayLevel, Frame -> False]
](*Plot everything*)
, {t, 0, 1, 1/100}];
ListAnimate[Join[Table[frames[[1]], {2}], frames, Reverse@frames]]
Licensing
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