File:01-Siebeneck E-11.svg

Uploaded by Petrus3743
Upload date 2018-05-19T14:58:09Z
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Summary

Description
Deutsch: Siebeneck, Näherungskonstruktion
English: Heptagon, approximation construction
Date
Source Own work
Author Petrus3743
Other versions
Siebeneck, Näherungskonstruktion als Animation
Heptagon, approximation construction as an animation
SVG development
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Näherungsonstruktion

Ergebnis

Bezogen auf den Einheitskreis r = 1 [LE]

  • Konstruierte Seitenlänge des Siebenecks in GeoGebra (Anzeige max. 15 Nachkommastellen) a=0,867767478235116[LE]
  • Seitenlänge des Siebenecks aSOLL=2sin(1807)=0,867767478235116[LE]
  • Absoluter Fehler der konstruierten Seitenlänge
Bis zu den max. angezeigten 15 Nachkommastellen ist der absolute Fehler Fa=aaSOLL=0,0[LE]
  • Konstruierter Zentriwinkel des Siebenecks in GeoGebra (Anzeige signifikante 13 Nachkommastellen) μ=51,4285714285714
  • Zentriwinkel des Siebenecks μSOLL=3607=51,4285714285714
  • Absoluter Fehler des konstruierten Zentriwinkels
Bis zu den angezeigten signifikanten 13 Nachkommastellen ist der absoluter Fehler Fμ=μμSOLL=0

Beispiel um den Fehler zu verdeutlichen

Bei einem Umkreisradius r = 1 Mrd. km (das Licht bräuchte für diese Strecke ca. 56 min), wäre der absolute Fehler der konstruierten Seitenlänge < 1 mm.


Approximate construction

Result

Based on the unit circle r = 1 [unit of length]

  • Constructed side length of the heptagon in GeoGebra (display max 15 decimal places) a=0.867767478235116[unitoflength]
  • Side length of the heptagon atarget=2sin(1807)=0.867767478235116[unitoflength]
  • Absolute error of the constructed side length
Up to the max. displayed 15 decimal places is the absolute error Fa=aatarget=0.0[unitoflength]
  • Constructed central angle of the heptagon in GeoGebra (display significant 13 decimal places) μ=51.4285714285714
  • Central angle of the heptagon μtarget=3607=51.4285714285714
  • Absolute error of the constructed central angle
Up to the indicated significant 13 decimal places is the absolute error Fμ=μμtarget=0

Example to illustrate the error

At a circumscribed circle radius r = 1 billion km (the light needed for this distance about 56 minutes), the absolute error of the 1st side would be < 1 mm.

Licensing

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